Moderator: Flannel Jesus
http://mathforum.org/library/drmath/view/55746.html wrote:Again, some examples can help make this clear:
_
0.1 = 1/9
__
0.12 = 12/99
___
0.123 = 123/999
and so on.
So, here's something to consider: What fraction corresponds to
_
0.9 = ?
It has to be something over 9, right?
_
0.9 = ? / 9
The _only_ thing it could possibly be is
_
0.9 = 9 / 9
right? But that's the same as 1.
Wonderer wrote:an obvious misrepresentation... thoughts?
Sorry mates, pretty much every professional mathematician on earth is of the opinion .999... does equal 1
You have no idea what you're talking about, and I suspect you never will. Do us all a favor and sew your fingers to your lips.
ladyjane wrote:so what number does .33333 [R] converge to
Wonderer wrote:until someone can make a response to my cube example my beliefs will remain unswayed
Already at this point, we disagree. I am of the opinion that the cube is exactly 1 inch in height so the rest of the example fails. The rest of the example is based on the assumption that the cube is *not* 1 inch in height which is what it attempts to show so it shows nothing.Wonderer wrote:imagine a cube that is .999[bar] inches in height.
You don't *actually* write them down. You don't need to. Think about it this way: We have the two infinite series of 3's. We place them next to each other and add each 3 to its counterpart.Wonderer wrote:you cannot possibly add them up because you could never finish writing them all down.
While it is true that mathematicians don't know everything, they know a LOT more than you about math and you have done little to convince me otherwise.Wonderer wrote:i don't care what the majority of Internet mathematicians think... all scientists once had to say the earth was the center of the universe or they would be severely punished... what's worse more than half of than half of them believed it...
333[bar]=1/3
1/3+1/3+1/3=3/3=1
QED
.333[bar]+.333[bar]+.333[bar]=1
It converges to 1/3.
.99999999.. [R]
IS NOT A SUM
yes .99999999 is 9/10 +9/100 etc
but that is not a real sum
if you sum all that then it converges to 1
but .999999 [r] is not a convergent number as it just goes on for ever it converges not to 1
when you say
1= .999999 [r]
ie
1= the number .999999 [R] sums to over infinty
you could also say
x= the number .33333333 [R] sums to over infinty
then
x would be bigger than .333333.[R]
then 3 * x would be bigger than 3 -which is a contradiction
you are misconstring a number for a convergent sum
PROOF
1/3 = .33333333 [R]
WHICH IS
3/10+ 3/100 etc
so what does that sum converge to
it might converge to a number bigger than .3333333.. [R]
THEN WHEN YOU ADD THREE OF THEM TOGETHER YOU GET A NUMBER BIGGER THAN 3-WHICH YOU DONT
just another example proving colin leslie deans point that maths ends in meaninglessness
no your denial proves nothing.Yorick wrote:]Already at this point, we disagree. I am of the opinion that the cube is exactly 1 inch in height so the rest of the example fails. The rest of the example is based on the assumption that the cube is *not* 1 inch in height which is what it attempts to show so it shows nothing.
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